F(x)=-6x^2+10x+1

Solution for F(x)=-6x^2+10x+1 equation:

(F)=-6F^2+10F+1

We move all terms to the left:

(F)-(-6F^2+10F+1)=0

We get rid of parentheses

6F^2-10F+F-1=0

We add all the numbers together, and all the variables

6F^2-9F-1=0

a = 6; b = -9; c = -1;
Δ = b2-4ac
Δ = -92-4·6·(-1)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{105}}{2*6}=\frac{9-\sqrt{105}}{12}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{105}}{2*6}=\frac{9+\sqrt{105}}{12}
$